sec²t -1 /sec²t = sin²t
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Jawaban:
Benar
Penjelasan dengan langkah-langkah:
[tex] \frac{ \sec ^{2}t - 1 }{ \sec {}^{2} t } [/tex]
[tex] \frac{ \frac{1}{1 - \sin(t) {}^{2} } - 1}{ \frac{1}{1 - \sin(t) {}^{2} } } [/tex]
[tex] \frac{1 - 1 + \sin(t) {}^{2} }{1} [/tex]
[tex] \frac{ \sin(t) {}^{2} }{1} [/tex]
[tex] = \sin(t) {}^{2} [/tex]
[answer.2.content]
